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Particles accelerate without a push (newsoffice.mit.edu)
73 points by rndn on Jan 25, 2015 | hide | past | favorite | 11 comments



Here is the paper:

http://www.nature.com/nphys/journal/vaop/ncurrent/full/nphys...

http://www.readcube.com/articles/10.1038/nphys3196?utm_campa...

PS: Didn't Nature decide to allow free real-only access to all papers? It appears that only the first page is freely accessible.


You can download the paper in pdf for free here: http://libgen.in/scimag/index.php?s=10.1038/nphys3196


> Didn't Nature decide to allow free real-only access to all papers? It appears that only the first page is freely accessible.

This is Nature Physics, not Nature. They are separate journals, albeit under the same publishing group.

Email me (my username @gmail) if you want a copy, or look at /r/scholar.


Nature physics is covered by the read-only access thing (48 journals are in total) [0]

The read only access link has to be generated by someone with access then shared, rather than them just making all the papers free to read.

0. http://www.nature.com/news/nature-promotes-read-only-sharing...

[Disclaimer: I work for an affiliated company]


Ahh, thanks. Quite a peculiar mechanism.

EDIT: So apparently I have to sign up for an account with yet another service, Readcube? No thanks...


> EDIT: So apparently I have to sign up for an account with yet another service, Readcube? No thanks...

I don't think so (I don't have access to nature journals so I can't check myself) but on the nature page for the article, if you click the share button it should be as a "shareable link" at the top.

This is based on the intro video here: http://readcube.wistia.com/medias/63iom1ywdy

It's a bit annoying that there's been a lot of talk about this being possible, but nowhere in the articles do people say how to do it.

> Ahh, thanks. Quite a peculiar mechanism.

Yeah, I suppose anything other than "the articles are now free to read" is going to be a bit odd to use.


Yep, you're right. Here's the link for anyone who wants it: http://rdcu.be/b1sE


Fantastic, thanks for going through this :)


If you assume examination, observation, etc are forces then this satisfies Newton's Law


OK, conservation of momentum; now what about conservation of energy?


Same thing, really. E = Sqrt((m*c^2)^2 + (pc)^2)




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