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It occurs to me that (per the second argument) these have Schläfli symbol {s,m} = {6,3}, {3,6} and {4,4} ...

for each of these, working out

    1/s + 1/m - 1/2 = 1/E
gives

    1/E = 0
... which makes sense (kind of) since those three cases are infinite regular tilings instead of regular polyhedra ...

(EDIT: Just noticed jonsen's comment here too, "infinihedron" suddenly makes sense to me :-) )




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