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If you choose your employees at random from the pool of applicants, and the applicants' abilities are normally distributed, then you're right that the employees' performance will be normally distributed. But I would expect any tech firm's hiring criteria to have at least some correlation with employees' performance, which means their performance will be biased towards the high end of the curve.

So no, the skill of the engineers probably shouldn't follow a normal distribution.




I think you are wrong. I think randomly drawing any significant number of people from a pool that isn't normally distributed is still likely to result in a normal distribution.

http://en.wikipedia.org/wiki/Central_limit_theorem


No, that's not quite right. Randomly picking people from a distribution should eventually end up giving the original distribution.

Taking n people from a pool m times, then the means of those m samplings will be normally distributed however (given the constraints of the CLT of course).


By definition, average is in the middle of whatever distribution they follow. Maybe median would be a more appropriate point to measure against though.


> By definition, average is in the middle of whatever distribution they follow.

Not necessarily the middle. In a skewed distribution, the average is still the sum of the samples divided by the number of samples, but it's not located at the middle (centerpoint) of the sample set.

> Maybe median would be a more appropriate point to measure against though.

You managed to get that exactly backwards. It's the median that's located at the middle of the distribution, not the mean. For a balanced distribution, they're the same, but for a skewed distribution, it's the mean that moves away from the "middle", not the median.




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