I don't know why you'd use a != a instead of isNaN(a). The former hides what you...

underwater on Feb 15, 2012 | parent | context | favorite | on: JavaScript: Warts and workarounds

I don't know why you'd use a != a instead of isNaN(a). The former hides what you're doing. Though treating two NaN values as equal doesn't even make sense in the first place.