It is the fault of the language to the extent that the purpose of the language is to make it easy to write correct programs, and UB makes it really hard (and in some cases impossible) to write correct programs.
It is just the opposite. UB is a clarification to tell programmers what the language considers to be undesired behavior. If they didn't say anything, it would be always a mystery if a certain construct was allowed or not, effectively making it compiler dependent. Compilers would also have less avenue for creating optimizations. In the next iterations of the C standard we may see more constructs classified as UB.
That sounds good in theory, but many things that are UB in C/C++ are UB because they are really hard to verify at compile time which makes them almost impossible to program around. Any signed addition in C is potential UB unless you have a proof that all numbers that will ever be input to the addition won't cause overflow (which is made harder because C doesn't define the size of the default integer types). Furthermore, no progress is UB which means that as a programmer, you have to solve the halting problem for your program before knowing whether it has a bug.
> many things that are UB in C/C++ are UB because they are really hard to verify at compile time which makes them almost impossible to program around
The second half of the sentence doesn't follow from the first. Take everyone's favorite example, signed integer overflow: all you have to do to avoid UB on signed integer overflow is check for overflow before doing the operation (and C23 finally adds features to do that for you).
Taking a step back, the fundamental thing about UB is that it is very nearly always a bug in your code (and this includes especially integer overflow!). Even if you gave well-defined semantics to UB, the semantics you'd give would very rarely make the program not buggy. Complaining that we can't prove programs free of UB is tantamount to complaining that we can't prove programs free of bugs.
It actually turns out that UB is actually extremely helpful for tools that try to help programmers find bugs in their code. Since UB is automatically a bug, any tool that finds UB knows that it found a bug; if you give it well-defined semantics instead, it's a lot trickier to assert that it's a bug. In a real-world example, the infamous buffer overflow vulnerability Heartbleed stymied most (all?) static analyzers for the simple reason that, due to how OpenSSL did memory management, it wasn't actually undefined behavior by C's definition. Unsigned integer overflow also falls into this bucket--it's very hard to distinguish between intentional cases of unsigned integer overflow (e.g., hashing algorithms) from unintentional cases (e.g., calculating buffer sizes).
My complaint here is that it took C more than 30 years between defining signed integer overflow as UB and providing programmers with standard library facilities to check if a signed integer operation would result in overflow.
I much prefer Rust's approach to arithmetic, where overflow with plain arithmetic operators is defined as a bug, and panics on debug-enabled builds, plus special operations in the standard library like wrapping_add and saturating_add for the special cases where overflow is expected.
My complaint here is that it took C more than 30 years ... I much prefer Rust's approach
That's an odd complaint. Rust didn't spring forth fully formed from the ether, it stands on the shoulders of C (and other giants of PL history). 30 years ago you couldn't use Rust at all because it didn't exist.
The reason the committee doesn't just radically change C in all these nice ways to catch up to Rust is because it would be incompatible. Then you wouldn't have fixed C, you'd just have two languages: "old C", which all of the existing C code in the world is written in, and "new C", which nothing is written in. At that point why not just start over from scratch, like they did with Rust?
The 2012 version is a bit more readable, and has unsigned integers:
For a signed integer type, the exception Constraint_Error is raised by the execution of an operation that cannot deliver the correct result because it is outside the base range of the type. For any integer type, Constraint_Error is raised by the operators "/", "rem", and "mod" if the right operand is zero.
For a modular type, if the result of the execution of a predefined operator (see 4.5) is outside the base range of the type, the result is reduced modulo the modulus of the type to a value that is within the base range of the type.
> all you have to do to avoid UB on signed integer overflow is check for overflow before doing the operation
All you have to do is add a check for overflow _that the compiler will not throw away because "UB won't happen"_. The very thing you want to avoid makes avoiding it very hard, and lots of bugs have resulted from compilers "optimizing" away such overflow checks.
> all you have to do to avoid UB on signed integer overflow is check for overflow before doing the operation (and C23 finally adds features to do that for you).
…making your code practically unreadable, since you have to write ckd_add(ckd_add(ckd_mul(a,a),ckd_mul(ckd_mul(2,a),b)),ckd_mul(b,b)) instead of a * a + 2 * a * b + b * b.
That's not the correct syntax for the ckd_ operations. They take 3 operands, the first being a pointer to an integer where the result should be stored. And they return a bool, which you need to check in a conditional. If you're just going to throw out the bool and ignore the overflows, why bother with checked operations in the first place?
See my other comment [1] which addresses the exact things you brought up here. Safe checked arithmetic is a new standard feature in C23. If no progress were not UB, then tons of loop optimizations would be impossible and then we couldn’t have nice things, like numpy.
> Any signed addition in C is potential UB unless you have a proof that all numbers that will ever be input to the addition won't cause overflow
This has always been the case. Standard C has always operated with the possibility that addition can overflow. The programmer or library writer is responsible to check if the used types are large enough. If you want to be perfectly sure you need to check for overflow. Making this UB has not changed the nature of the issue.
> is made harder because C doesn't define the size of the default integer types
They correctly made this implementation defined. But C now has different byte sized integer types if you want to be sure.
Is the improved performance of C over say Java, or Rust (which both have much less undefined behaviour -- Java almost none) worth the pain and bugs which have been caused by UB?
Honestly, I don't think so, and as computers get more powerful and the amount of the world which relies on their correct functioning grows, I feel the arguments for UB become increasingly difficult to justify.
I went to look up undefined behaviour in Rust and I got this scary warning:
Warning: The following list is not exhaustive. There is no formal model of Rust's semantics for what is and is not allowed in unsafe code, so there may be more behavior considered unsafe. The following list is just what we know for sure is undefined behavior. Please read the Rustonomicon before writing unsafe code.
After the warning was a list of many of the same types of things that are undefined behaviour in C. In addition, there’s a bunch more undefined behaviour related to improper usage of the unsafe keyword.
So I don’t think you get a free lunch with Rust here. What you get is a “safe” playground if you stay within the guard rails and avoid using the unsafe keyword. But then you are limited to writing programs which can be expressed in safe Rust, a proper subset of all programs you might want to write.
Furthermore, the lack of a formal specification for Rust is one area where it lags behind C, a standardized language. All of the undefined behaviour in C is decreed and documented by the standard, having been decided by the committee. Rust, on the other hand, may have weird and unpredictable behaviour that you just have to debug yourself, which may or may not be compiler bugs.
I agree rust isn’t perfect, but I think you underestimate the value of “safe” code.
I often write programs that have unsafe code. However, the unsafe code is never more than 100 lines, which means I have a very small amount of code to reason about — Rust users expect (of course, you as a programmer has to enforce) that it should be possible to cause UB from safe code, so my “safe interface” to my unsafe code ensures my code can’t cause UB, no matter what I call.
On problem with Rust is generally when you mess up it panics — I think that’s better than buffer overflows and the like, but still not a good user experience.
This means there is a very small amount of code I have to really think about, while in C or C++, basically any place x[i] appears (regardless of if x is a pointer or a std::vector).
You can of course write safe C code, people do, but it’s hard, and it only takes one slip up anywhere in your program to blow it.
In one sense, C is the unsafe code block for myriad other languages, like Python. Python users don’t want to deal with undefined behaviour either. They want to write their high level code in NumPy or PyTorch and just have everything work very fast.
Little do they know: they rely on C for those libraries and for things like ATLAS and LAPACK, which implement the underlying numerical linear algebra code. Well, it turns out that ATLAS relies pretty heavily on optimizing C compilers to generate optimal code on many different platforms. At the bottom of all this are the many loop optimizations included in compilers which, thanks to undefined behaviour in the C spec, are able to assume that code is always on the happy path.
It also turns out that Rust includes bindings to ATLAS and LAPACK. I would imagine at some point people might want to write a new linear algebra package in pure Rust. I think it’ll be quite difficult to match the performance of those two in safe Rust, but we’ll see.
C does not have a formal specification either. It has a standard's document that is written using formal English, but it does not provide a formal spec of C's semantics. A formal spec of a programming language's semantics would entail using a formal semantic model such as operational or denotational semantics. Some programming languages do specify the formal semantics for the entire language or some subset of the language but C is not one of them.
Your claim that the C Standard lists all undefined behavior is actually false. The C Standard only lists out the explicit list of undefined behavior, but it does not list out the implicit list of undefined behavior. There have been efforts to make just such a list but it's an incredibly difficult task.
