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A lower bound for latency to the 'other side of the earth':

(20 000 km) / the speed of light = 66.712819 milliseconds

http://www.google.dk/search?sourceid=chrome&ie=UTF-8&...




Ping measures the round-trip time, so it would really be twice that.


The 20k figure is an approximate circumference of the Earth.


24,000 miles, not km.


its 40k, not 20k.


The circumference of the earth is ~40k km, which would make "the other side of the earth" ~20k.


Yeah, that's the point.


Since we're talking hypothetically, the lower boundary would really be the diameter of Earth.

    12,756.2 km / c = 42.5501031 ms
http://www.google.com/search?q=diameter+of+earth+%2F+the+spe...


> 12,756.2 km / c = 42.5501031 ms

It's worth pointing out that we're looking at more like 0.65c, through optical fibre. This would also be ignoring routing infrastructure/processing time and network prioritisation.


not with a molton core, unless I misunderstood you...


Fiber optic cables may not be able to penetrate the molten core of the Earth, but there is no law of physics that prevents information from traveling through the core of the Earth. Compare this to the speed of light, which is an absolute upper bound on how quickly information can propagate. There is simply no way, in this Universe, to do better than the straight-line distance through the center of the Earth.


You could transmit magnetic waves at about the speed of light.




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