>>> sorted({w: comment.split().count(w) for w in comment.split() if comment.split().count(w) > 1}.items(), key=lambda x: -x[1])[:3]
[('I', 9), ('Hetzner', 7), ('that', 7)]
7 sentences, 7 occurrences of "Hetzner". It really does read like a CEO-optimized advertisement.