it might be optimized to a memset, but it's the clone codepath, as opposed to the u8 specialization codepath as discussed in the article
But the original commenter is talking about how the benchmark isn't useful because it doesn't touch memory, but you get similar results even if you do touch memory.
it might be optimized to a memset, but it's the clone codepath, as opposed to the u8 specialization codepath as discussed in the article
But the original commenter is talking about how the benchmark isn't useful because it doesn't touch memory, but you get similar results even if you do touch memory.