On: Parse, don’t type-check

[zelphirkalt]

I don't see anything surprising. "is" has higher prevalenz than "in" and that's it. Or am I misreading something?

[vanni → zelphirkalt]

It's not a matter of operator precedence for two reasons:

1) "in" and "is" have same precedence, and group left to right (see https://docs.python.org/3/reference/expressions.html#operato...)

2) you'll have runtime error:

  In [1]: def c():
     ...:     return (1 in ([1,2,3] is True))
  
  In [2]: c()
  ...  
  TypeError: argument of type 'bool' is not iterable

It seems related to CPython bytecode compiler implementation, the two functions are parsed in a different way, parentheses make the compiler go on a different path... but I'd like to understand why, without diving into CPython source code :) Anyone?

[morelisp → zelphirkalt]

If this was the reason you'd get a TypeError, since there's no `bool.__contains__`.