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on March 20, 2020
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Mathematica v12.1
Does that mean I can solve a system of equations in vector form, e.g. solve this for X:
A·X=d1
B·X=d2
(A⨯B)·X=(A⨯B)·C
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Search:
A·X=d1
B·X=d2
(A⨯B)·X=(A⨯B)·C