That makes sense, but theres still the problem that, even if you have 3 in a row that you think have a higher probability of occurring in the hidden part, they can still be X or O, not necessarily winning. Maybe theres a statistical edge in knowing that, but I doubt that would give you an edge of 90%.
Also, that seems to indicate the issue is due to the overall structure of the problem of choosing numbers for a game like this, while I got the sense from the article that the problem was more due to the algorithm the company used to control winners and losers (maybe I'm wrong on that). If it is due to how the company controls wins in some way, I could see how observing 3 in a row of singles more often than expected by a random distribution (whatever the distribution is for choice of number and choice of spot on the board) is a giveaway to some nonrandomness introduced by their algorithm. But if you were to approach it by finding divergences from this distribution, wouldn't you need a lot of tickets before you could infer this?
In any case - any guess on the expected number of tickets you'd have to have to discover a flaw like this?
Also, that seems to indicate the issue is due to the overall structure of the problem of choosing numbers for a game like this, while I got the sense from the article that the problem was more due to the algorithm the company used to control winners and losers (maybe I'm wrong on that). If it is due to how the company controls wins in some way, I could see how observing 3 in a row of singles more often than expected by a random distribution (whatever the distribution is for choice of number and choice of spot on the board) is a giveaway to some nonrandomness introduced by their algorithm. But if you were to approach it by finding divergences from this distribution, wouldn't you need a lot of tickets before you could infer this?
In any case - any guess on the expected number of tickets you'd have to have to discover a flaw like this?