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NASA Maps Surface Changes from California Quakes (nasa.gov)
89 points by infodocket on July 10, 2019 | hide | past | favorite | 17 comments



That is a very cool finding. Though I must say that visualizing the data with a jet colormap and no legend is a little disrespectful to anyone who is sober.


This was my initial reaction as well, but the article mentions that

> Each color cycle represents 4.8 inches (12 centimeters) of ground displacement either toward or away from the satellite.

...so what we're actually interested in is counting the number of cycles through the color map between two points, for which jet actually seems like a perfectly good choice.

jofer explains in their comment why the data is shown this way: https://news.ycombinator.com/item?id=20398703


> a jet colormap and no legend

this is very standard for interferometry (that represents a height difference modulo some step). There is no useful "legend" that you can associate to this colormap. The only information missing is the step between cycles of the colormap, which is given.


The aftershocks going on here (most small, but higher frequency than usual) is interesting to look at, if not a little disturbing :). A 4.0 in the last hour too (6:48 PM).

http://scedc.caltech.edu/recent/Maps/118-36.html


> Each color cycle represents 4.8 inches (12 centimeters) of ground displacement in the radar line-of-sight.

Is there a legend somewhere, or at least a max? I'm not sure what is meant by "color cycle".


You're looking at an interferogram.

The method used here can't measure displacement directly. It measures a phase difference between two radar images. Turning this into a map of displacement is non unique in the presence of noise and limited spatial resolution.

That's why you'll see this type of data displayed in this way. The rainbow palette is mostly convention, but either way, it's the most direct view of what actually measured.

It's also kinda pretty, i.m.o...


It is certainly pretty. But I'm still not clear what it means.

OK, so the radar is measuring distance between the satellite and reflecting surface. They're compairing data from July 8, 2019 and April 8, 2018. I'm guessing that the two images look pretty much the same. Especially given limited spatial resolution.

But ELI5, what does the interference pattern show? I mean, are there 12 cm amplitude waves of vertical surface displacement? Something like frozen S waves?


An earthquake is rocks sliding past each other. What you're looking at here is a measure of how much they moved. (It doesn't "slide back" afterwards -- the motion is permanent.) For an earthquake of this size, the motion will be on the order of a few meters.

------------

In a bit more detail, the radar can't measure distance precisely enough to detect the movement. The distance measured before and after by radar is the same, within error. However, there's another part of the radar signal beyond just how long it takes to travel. That second part is the phase of the returned signal. Imagine the first time we imaged a small area, we got a return waveform that looked like this (zero phase):

    /\  /\  /\   
      \/  \/  \/
but then the next time we got back a slightly different result (270 degree phase):

    \  /\  /\  / 
     \/  \/  \/
The difference is shape of the returning signal is a phase shift. The radar wave is shifted slightly

We know that it moved at least three quarters wavelength in the ascii art example above. However, we'd get the same result if it moved ten and three quarters, though. We can measure part of the change very precisely, but the bulk of the motion looks the same to us. We're looking at that fined-grained part of the motion (phase difference) not the overall motion itself.

In programming terms, we're looking at the result of a modulo operator.


> we'd get the same result if it moved ten and three quarters

And also the same if it moved one quarter wavelength in the opposite direction.


Thanks.

I see that the ALOS-2 SAR uses L band, which seems to mean 1-2 GHz (30-15 cm). So maybe the ALOS-2 actually uses 12 cm?

So does that mean that the pattern shows something like contour lines?


Yep! You can think of the bands as contour lines of deformation.


Hey, thanks.


If I understand the right thing, from one red "line" to another, there has been a 4.8 inch displacement between the two photos.


Since the description says each color cycle represents 4.8 inches, I would say if you trace a line from one red pixel across the blue pixels to another red pixel, you've traversed a cycle, and you've increased or decreased displacement from the reference by 4.8 inches.


I think they just mean how the maps cycles through the colors. The contours for the same color are apart by multiples of a cycle.


Relatedly, InSAR images of the Kilauea volcano area:

https://www.jpl.nasa.gov/spaceimages/details.php?id=PIA13910

And land subsidence due to groundwater pumping in California’s Central Valley, showing motion of up to 70 cm (!):

https://www.jpl.nasa.gov/spaceimages/details.php?id=PIA16293


At first glance, this looks very much like some Julia sets.




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