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If you take the numbers from the article as accurate, 33 megejoules at Mach 7 means the weight is ~15kg (assuming I got all my conversions and orders of magnitude right, feel free to do your own e=1/2mv^2 calculation...)



I got ~10kg from the 2500m/s number, and under 12kg from the Mach 7 number. Google agrees:

http://www.google.com/search?q=2*33megajoules/(2500+m/s)^2+i...

http://www.google.com/search?q=2*33megajoules/(7+*+speed+of+...


Projectile speed will be much less after it has travelled 100km.




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