Yes, so there are n! = 87,178,291,200 different permutations of those 14 sequences. You want to watch the 14 episodes in every possible order, ie in each of those permutations. You could just watch all of those permutations consecutively, for n x n! episodes in sequence, which would be 1,220,496,076,800 episodes (or, well, 14 episodes per permutation).
However, you can do much better, exploiting overlap, using only 93,884,313,611 episodes, which is really quite remarkable, because it is just 1.08 episodes per permutation.
Example with 3 (from the article):
3! = 6 permutations
Bad way to watch all: concatenate all permutations
A) 123 132 213 231 312 321 (= 3*6 = 18 episodes, or 3 episodes per permutation)
Good way to watch all permutations:
B) 123121321 (= 9 episodes, or 1.5 episodes per permutation)
Note that each of the permutations above in A is contained in the string at B).
However, you can do much better, exploiting overlap, using only 93,884,313,611 episodes, which is really quite remarkable, because it is just 1.08 episodes per permutation.
Example with 3 (from the article):
3! = 6 permutations
Bad way to watch all: concatenate all permutations
A) 123 132 213 231 312 321 (= 3*6 = 18 episodes, or 3 episodes per permutation)
Good way to watch all permutations:
B) 123121321 (= 9 episodes, or 1.5 episodes per permutation)
Note that each of the permutations above in A is contained in the string at B).