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the8472
on Oct 27, 2018
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parent
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The Periodic Table of Data Structures [pdf]
One way to do this is to send a bloom filter as index and then return the elements that are not part of the bloom filter.
jpitz
on Oct 27, 2018
[–]
But what about the false positives?
jwhitlark
on Oct 27, 2018
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parent
[–]
Well, I would assume the receiving node would verify that each entry was actually needed.
jpitz
on Oct 27, 2018
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root
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parent
[–]
Aren't the false positives in this situation representative of set elements that node b thinks that node a has but really does not?
the8472
on Oct 27, 2018
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root
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parent
[–]
Right, the solution I remembered was a bit more complex, it required counting bloom filters and a subtraction operation to get a filter for the set difference. But the paper mentioned in a sibling comment claims to have even less overhead.
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