Each proton would, at the full power of 7 TeV, have 1.12 microjoules of energy. 1.15x10^11 protons per pulse, 2808 pulses per beam and two beams, one of antiprotons, and one of protons; for a total energy of 352,235,520 joules. 87 kilograms of TNT.[1][2]
Your hand would evaporate fairly quickly, then turn into a plasma, then get hot enough to start radiating x-rays. There would be quite a lot of bremsstrahlung from the hyperenergetic protons punching through the cloud of plasma, and producing showers of secondary radiation,[3] which means you would be quite well irradiated by the time the shockwave from the explosion killed you.
1: All this is straight from the wikipedia page, but I double checked the math.
2: I'm not including energy liberated from antimatter annihilation energy, since the total mass of the antiprotons is quite small.
Typing that out, it sounds like a pretty lame excuse. Let's do the math.
3.2292x10^14 protons per beam. Atomic weight of 1, of course, so:
(3.2292x10^14)/(6.0221415x10^23)[4] = 5.362212x10^-10 grams. .536 nanograms of antimatter.
Since annihilating antimatter gets you 9x10^13 joules per gram, you get... 48,259.9089 joules. That's actually larger than I expected, but .01% of the kinetic energy of the beam.
3: Just how much secondary radiation, I don't know, since that depends on the density of the cloud of plasma, which would change over time, be pretty anisotropic, and be a general pain in the ass to model.
4: Avogadro's constant
Buncha edits: forgot HN uses the asterisk to style text.
Can't edit this now, of course, but as fjh pointed out elsewhere, I confused the details of the LHC for the LEP, partially. The LHC collides protons and sometimes lead nuclei; but at no point collides antiprotons.
Each proton would, at the full power of 7 TeV, have 1.12 microjoules of energy. 1.15x10^11 protons per pulse, 2808 pulses per beam and two beams, one of antiprotons, and one of protons; for a total energy of 352,235,520 joules. 87 kilograms of TNT.[1][2]
Your hand would evaporate fairly quickly, then turn into a plasma, then get hot enough to start radiating x-rays. There would be quite a lot of bremsstrahlung from the hyperenergetic protons punching through the cloud of plasma, and producing showers of secondary radiation,[3] which means you would be quite well irradiated by the time the shockwave from the explosion killed you.
1: All this is straight from the wikipedia page, but I double checked the math.
2: I'm not including energy liberated from antimatter annihilation energy, since the total mass of the antiprotons is quite small.
Typing that out, it sounds like a pretty lame excuse. Let's do the math.
3.2292x10^14 protons per beam. Atomic weight of 1, of course, so:
(3.2292x10^14)/(6.0221415x10^23)[4] = 5.362212x10^-10 grams. .536 nanograms of antimatter.
Since annihilating antimatter gets you 9x10^13 joules per gram, you get... 48,259.9089 joules. That's actually larger than I expected, but .01% of the kinetic energy of the beam.
3: Just how much secondary radiation, I don't know, since that depends on the density of the cloud of plasma, which would change over time, be pretty anisotropic, and be a general pain in the ass to model.
4: Avogadro's constant
Buncha edits: forgot HN uses the asterisk to style text.