K does a thing (like J I think?) where it's scan/reduce returns each subsequence/intermediate-value as it goes which is what makes that problem so trivial in K.
The K "over" adverb (/) is like a conventional reduce/accumulate/fold. The K "scan" adverb (\) produces a list of the intermediate results. Having both is extremely handy.
If the verb argument of over/scan takes a single argument (rather than two), the adverbs will iterate to a fixed point. As before, "/" will return the final result and "\" returns all the intermediates.
Oh wait, so you're not preserving the subsequence, you just preserving the sum. So it's a standard scan. So my original translation is correct, my subsequence preserving version is doing a bit more than this by preserving the subarray as well as the sum.
