> Knowing how the floating point number is packed, we know a right shift is equal to divide by two and negate it.
Shifting an IEEE754 floating point number does not have that effect.[0] The fact that it doesn't do that is the source of the "mystery" of fast inverse square root.
Shifting an IEEE754 floating point number does not have that effect.[0] The fact that it doesn't do that is the source of the "mystery" of fast inverse square root.
[0] https://gist.github.com/jessedhillon/386fa964e822e529f6c1