On: A = F/m, So Keep Your Foot on the Gas

[simon_]

Acceleration = F/m implies Position = F/2m(t^2) + k1(t) + k2

That's quadratic, but definitely not exponential, and doesn't really look like the curve he drew.

I know the guy's argument doesn't really depend on the shape of the curve, but it's a pet peeve of mine that exponential growth is always presented in an inaccurate way.

EDIT: fixed embarrassing calculus error

[jedbrown → simon_]

The curve doesn't even look exponential since it seems to become infinite at finite time, more like 1/(T-t).

[ygd_coder → simon_]

Actually:

x = 1/2 * a * t^2 + v0 * t + x0

[simon_ → ygd_coder]

doh, fixed.