DIFF's comments

On: No bullshit guide to math and physics

[DIFF]

0 \in N, 5 \in N => (0/5) \in Q. Therefore 0 \in Q. QED.

[v-yadli → DIFF]

Watch out for your proof. Q is constructed as a field with + and x only. The availability of the inverse operator is not well documented :-D

[chris_wot → DIFF]

\in?

[bane → chris_wot]

\in means "in the set of"

Given the definition "The definition of a rational number is a number that can be expressed as the quotient of two integers where the denominator is not 0."

Let N be the set of all integers and Q be the set of all rational numbers.

Trivially 0 is in the set N, 5 is in the set N

by the definition 0/5 is in Q. Therefore 0 is in Q. QED.

[chris_wot → bane]

Ah, I see! Deleted my old comment. Nice :-)